VLSM Exercise

Exercise 3: We want to divide 192.168.10.0 which is class C network, into four networks, each with unequal number of IP address requirement as shown below:

•  Subnet A: 32 host.
• Subnet B: 8 host.
• Subnet C: 22 host.
• Subnet D: 60 hosts.

Solution:

Organize, high - low

·         Subnet D: 60 hosts.

Host = 2⁶ = 64 – 2 = 62                      N = 2² = 64

·         Subnet A: 32 host.

Host = 2⁶ = 64 – 2 = 62                      N = 2² = 64

·         Subnet C: 22 host.

Host = 2⁵ = 32 – 2 = 30                      N = 2³ = 32

·         Subnet B: 8 host.

Host = 2⁴ = 16 – 2 = 14                      N = 2⁴ = 16

Subnet	Network Name	Network Address	Valid Host Range	Broadcast Address	Subnet Mask
22 = 64	D	192.168.10.0	192.168.10.1 - 192.168.10.62	192.168.10.63	255.255.255.192
22 = 64	A	192.168.10.64	192.168.10.65 - 192.168.10.126	192.168.10.127	255.255.255.192
23 = 32	C	192.168.10.128	192.168.10.129 - 192.168.10.158	192.168.10.159	255.255.255.224
24 = 16	B	192.168.10.160	192.168.10.161 - 192.168.10.174	192.168.10.175	255.255.255.240

Exercise 4: Given network of 201.4.3.0/24, subnet the network in order to create the subnetworks with the following:

• Office 1 – 14 hosts.
• Office 2 – 60 hosts.
• Office 3 – 32 hosts.
• Office 4 – 7 hosts.
• Office 5 – 15 hosts.

Solution:

Organize, high - low

·         Office 2 – 60 hosts.

Host = 2⁶ = 64 – 2 = 62                      N = 2² = 64

·         Office 3 – 32 hosts.

Host = 2⁶ = 64 – 2 = 62                      N = 2² = 64

·         Office 5 – 15 hosts.

Host = 2⁵ = 32 – 2 = 30                      N = 2³ = 32

·         Office 1 – 14 hosts.

Host = 2⁴ = 16 – 2 = 14                      N = 2⁴ = 16

·         Office 4 – 7 hosts.

Host = 2⁴ = 16 – 2 = 14                      N = 2⁴ = 16

Subnet	Network Name	Network Address	Valid Host Range	Broadcast Address	Subnet Mask
22 = 64	2	192.168.10.0	192.168.10.1 - 192.168.10.62	192.168.10.63	255.255.255.192
22 = 64	3	192.168.10.64	192.168.10.65 - 192.168.10.126	192.168.10.127	255.255.255.192
23 = 32	5	192.168.10.128	192.168.10.129 - 192.168.10.158	192.168.10.159	255.255.255.224
24 = 16	1	192.168.10.160	192.168.10.161 - 192.168.10.174	192.168.10.175	255.255.255.240
24 = 16	4	192.168.10.176	192.168.10.176 - 192.168.10.190	192.168.10.191	255.255.255.240